How far would you have to go toward
the moon so that the pulls of gravity of both Earth and Moon are equal?
Mearth=6E24Kg,
Mmoon=7.35E22Kg,
separation of Earth and moon = 3.844E8meters
There are two forces in question here... the gravitational
force of the Earth and the gravitational force of the moon.
We set these two equal to each other and solve for "r"
and "R".
Fearth= Gmobjectmearth/r2to earth Fmoon= Gmobjectmmoon/R2to moon
set the two equal to each other...
Gmobjectmearth/r2to earth =Gmobjectmmoon/R2to moon
Divide everything by "G" and "mobject" cleans things up a bit...
mearth/r2to earth =mmoon/R2to moon
We already know the distance from Earth to the moon = 384400000m, so
R+r = 384400000
So if we isolate either "r" or "R", we can insert that value into the other equation...
R + sqrt(R2mearth/mmoon) = 384400000
Square everything to get rid of those unsightly parantheses...
R2 + R2mearth/mmoon=1.478E17
Fill in the masses of Earth and moon...
R2 + R2(6.0E24 /7.35E22 kg) = 1.47E17
82.63R2 = 1.47E17
R = 4.22E7meters from
the moon
and
r = 3.42E8meters
from Earth
If you were asked what % of the way you'd have to go to the moon...