How far would you have to go toward the moon so that the pulls of gravity of both Earth and Moon are equal? Mearth=6E24Kg, Mmoon=7.35E22Kg, separation of Earth and moon = 3.844E8meters
There are two forces in question here...  the gravitational force of the Earth and the gravitational force of the moon.
We set these two equal to each other and solve for "r" and "R".

Fearth= Gmobjectmearth/r2to earth         Fmoon= Gmobjectmmoon/R2to moon

set the two equal to each other...

Gmobjectmearth/r2to earth =Gmobjectmmoon/R2to moon

Divide everything by "G" and "mobject" cleans things up a bit...

mearth/r2to earth =mmoon/R2to moon

We already know the distance from Earth to the moon = 384400000m, so

R+r = 384400000

So if we isolate either "r" or "R", we can insert that value into the other equation...

r = sqrt(R2mearth/mmoon goesinto R+r = 384400000 for "r"...

R + sqrt(R2mearth/mmoon) = 384400000

Square everything to get rid of those unsightly parantheses...

R2 + R2mearth/mmoon=1.478E17

Fill in the masses of Earth and moon...

R2 + R2(6.0E24 /7.35E22 kg) = 1.47E17

82.63R2 = 1.47E17

R = 4.22E7meters from the moon
and
r = 3.42E8meters from Earth

If you were asked what % of the way you'd have to go to the moon...

3.42E8/3.844E8= 90% of the way there