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divided by some "test" charge (Coulombs)...1Volt=1Joule/Coulomb voltage is often referred to as "potential difference" |
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amount of push (volts) / amount of actual current flow (amps) |
reduces flow of current |
amps=volts/ohms,
volts=amps*ohms, ohms=volts/amp
Remember the watt? We know that electrical
devices have wattage, so there must be a way to express the watts of an
appliance...
amps*volts
= Coulomb/sec * Joule/Coulomb = Joule/sec = watts = Power
Put another way, amps*volts=power, and since amps=volts/ohms, then Power= volts2/ohms, and we could also substitute I*R for V, yielding Power=I2/R.