A 800Kg truck skidding against a road surface has m
=
.6. What frictional force is present?
USE: mN
.6*1200Kg*9.8m/s/s = 7056N
What is the magnitude of the car's acceleration?
a = F/m = 7056N / 1200Kg = 5.9m/s/s NOTE: Since the question asks only for magnitude, we don't need to specify that our answer is negative.
If it were originally coasting at 15m/s, what would its stopping distance be?
Vf2 = Vo2 + 2aDx
0 = (15m/s)2 + (2)(5.9m/s/s)(x)
x = 225m2/s2 / 11.8m/s/s = 19.1m