Here is an old test, the questions are in the left column and the answers are in the right.  I would suggest you avoid the temptation to just study both columns.... I would rather see you write the questions then try solving them on your own before reading the answers.

A crow flies to a point that is 5 miles away, and at 75 degrees above the +X axis.  How far North of the start point is the crow?	Want Y coordinate, so use X=5miles*sin75=4.8miles
Two forces act on an object.  Force "A" is 17 units, and directed at 40 degrees below the +X axis.  Force "B" is 22 units and directed at 10 degrees above the +X axis.  Find the resultant vector's length and direction.	First, break both vectors into their X and Y components. (remember that A's Y component is negative) Ax = 17cos40 = 13 Ay = 17sin40 = -10.9 Bx = 22cos10 = 21.66 By = 22sin10 = 3.8 Then add the X's together and the Y's... Cx = 13+21.66 =  34.66 Cy = -10.9+3.8 = -7.1 To find C's length, use pythagorean theorem... C = sqrt(Cx2+Cy2) = 35.4 units Use tangent to get direction... q = inv tan(Cy/Cx) = 11.6 degrees below +X axis
Given this formula; Range=(Vo2/g)sin2qexplain why the maximum range of a projectile occurs at 45 degrees. Assume Vo and g are constants.	the sin of 2q is 1 at 45 degrees.  Any other angle gives a value between zero and one.
A bomb is dropped from a plane 200m up.  It lands 1500m away from a spot directly under the drop site.  What is the plane's speed?	first find time to hit ground from h=200m... t = sqrt(2h/g)=sqrt(400/9.8)= 6.4sec now we know t and d, so s= d/t... s = 1500m/6.4s = 234.8 m/s
Fill in the table for a projectile launched at 200m/s at an angle of 65 degrees above horizon. seconds Yheight Xdistance 2 8 10	To solve this, we need Vx and Vy... Vx = 200cos65 = 84.5m/s Vy = 200sin65 = 181.3m/s The Ycoordinate is given by  Y=Yo + (Vy)t - at2/2  (a is gravity = 9.8m/s/s) Yat2sec=0+(181.3*2)-9.8*22/2=343m Yat8sec=1137m Yat10sec=1323m The Xcoordiante is given by (Vx)t Xat2sec=84.5*2=169m Xat8sec=676m Xat10sec=845m