Your two vecors cause the system (you, friend, and rope)
to not move. This situation is called static
equilibrium.
The situation looks like this...
Each arrow is the same length.
WITH a little imagination, you can
extend this situation....
If three people with equal strength pull on a tent stake,
one in each of these directions: north, east, and west.... Where
would a fourth person have to pull (with
the same strength) in order to create static equilibrium?
Hopefully, your common sense voice is saying, "SOUTH!!!".
Here is another easy example....
Vector A is 40 units long and points at +45°. Find
length and direction of a new vector "B" that would cancel out vector A.
Mathematically speaking, we want this statement to be true: A=-B
COMMON SENSE METHOD: Vector B must be same strength as A, so is 40 units, and must point in opposite direction as Vector A, so is at 45° + 180° = 225°
MATH METHOD:
find Ax and Ay, then use their opposites to get "B"
Ax = 40cos45 = 28.28 units ===>
therefore B has Bx = -28.28 units
Ay = 40sin45 = 28.28 units ===>
therefore B has By = -28.28 units
Use Pythagorean Theorem to get length
of B.... sqrt(-28.28² + -28.28²) = 40
units
Use tangent to get angle... q
=
inv tan(-28.28/-28.28) = 45°+180° = 225°
This technique can be applied
to numerous situations, many we will see later when we discuss momentum
and force. For now, log into Lecture
OnLine and solve: "A+B=-C" and "vector T/F"